0=16t^2+32

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Solution for 0=16t^2+32 equation: 



0=16t^2+32

We move all terms to the left:

0-(16t^2+32)=0

We add all the numbers together, and all the variables

-(16t^2+32)=0

We get rid of parentheses

-16t^2-32=0

a = -16; b = 0; c = -32;
Δ = b2-4ac
Δ = 02-4·(-16)·(-32)
Δ = -2048
Delta is less than zero, so there is no solution for the equation

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